Comments (1)
any86
commented on May 18, 2024
1
可以啊, 现有的做个组合即可, 也可以单独做个"或"的判断: if(cRE.test(str) || eRE.test(str))
你要的"英文或汉字"
/^(?:(?:[\u3400-\u4DB5\u4E00-\u9FEA\uFA0E\uFA0F\uFA11\uFA13\uFA14\uFA1F\uFA21\uFA23\uFA24\uFA27-\uFA29]|[\uD840-\uD868\uD86A-\uD86C\uD86F-\uD872\uD874-\uD879][\uDC00-\uDFFF]|\uD869[\uDC00-\uDED6\uDF00-\uDFFF]|\uD86D[\uDC00-\uDF34\uDF40-\uDFFF]|\uD86E[\uDC00-\uDC1D\uDC20-\uDFFF]|\uD873[\uDC00-\uDEA1\uDEB0-\uDFFF]|\uD87A[\uDC00-\uDFE0])+|[a-zA-Z])$/
from any-rule.
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from any-rule.