Using YaLinqo with Slim Framework about yalinqo HOT 8 CLOSED

@RODOBTA
What are your problems exactly? Show your code, error messages you receive etc.

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@Athari
It does not generate any error, it just returns an empty object, I do not know if I'm missing any reference, or upload a file

My code:

My references:

Result:

If I omit the part of the first image, this is the result:

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@RODOBTA
Not sure what IDE you're using and how "Pretty" works, but if you switch to "Raw" you'll probably see that you're inspecting an iterator class (Enumerable) with private fields. As getting values from iterators changes their state, IDEs can't display their contents in a nice way without breaking the code.

In general, YaLinqo produces iterators, not pure arrays. You need to iterate over them with foreach (preferable) or convert them to arrays or some other format (using toList, toArray, toDictionary, toJSON etc.) or reduce them to single values (min, max etc.).

If the code you quoted is used by a method which expects arrays (I don't know how Slim works), then you can append ->toList() to your method chain:

return from($result)->where(function($item) { return $item['Id'] == 0; })->toList();

That would also allow IDE on inspect the result.

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Using Visual Studio Code:
This is my code:

These are my data:

What I want to get from $result, are the items that have Padre= 0

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@RODOBTA

1. I don't see ->toList() in your code.
2. I don't see the error you receive.
3. Items of your $result array seem to be objects, not arrays, so $item['Padre'] syntax isn't supposed to work (members are accessed with -> operator).

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@Athari
I have modified the form of access to the property, and add the toList ():

this is the error that I receive

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@RODOBTA
Class members in PHP are accessed using -> operator, not .. You need to write ->toList(), not .toList().

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@Athari
It worked perfect, I had not noticed the error in .toList(), replaced by ->toList() now it works great. Thank you very much.

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