WebSockets handshake request query string not available through params about telegraph HOT 2 CLOSED

QueryString parameters and POST data do not end up in the params dictionary. The name params might be a bit confusing, because at the moment only the route parameters end up in the params dictionary.

If you like you can create a HTTPRequestHandler that takes the QueryString parameters from the HTTPRequest and adds them to the request's params dictionary:

import Foundation
import Telegraph

public class HTTPRequestParamsHandler: HTTPRequestHandler {
  public func respond(to request: HTTPRequest, nextHandler: HTTPRequest.Handler) throws -> HTTPResponse? {
    // Extract the QueryString items and put them in the HTTPRequest params
    request.uri.queryItems?.forEach { item in
      request.params[item.name] = item.value
    }

    // Continue with the rest of the handlers
    return try nextHandler(request)
  }
}

Then add the handler to the server's handlers:

let paramsHandler = HTTPRequestParamsHandler()
server.httpConfig.requestHandlers.insert(paramsHandler, at: 0)

Note that this will overwrite any route parameters with the provided querystring parameters. But this gives you the flexibility to handle it to your likings.

from telegraph.

@Zyphrax The sample handler is exactly what I'll need and it seems like a neat way to achieve it. Thanks!

from telegraph.