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moodymudskipper avatar moodymudskipper commented on July 2, 2024

Would be miraculously a 3 lines fix with rlang::is_expression() if it returned FALSE when the call hides attributes. See r-lib/rlang#1475

We might have to reprogram is_expression(), the logic doesn't seem extractable easily.
Or we implement another recursive logic but it won't be half as pretty.

from constructive.

moodymudskipper avatar moodymudskipper commented on July 2, 2024

There seems to be a logic in rlang to avoid recursion, probably for some stack issues since they stop at 100 anyway. But for our use case this should do it:

is_expression2 <- function(x) {
  if(!is.null(attributes(x))) return(FALSE)
  if (rlang::is_syntactic_literal(x) || rlang::is_symbol(x)) return(TRUE)
  if(!rlang::is_call(x)) return(FALSE)
  all(vapply(x, is_expression2, logical(1)))
}

And we tweak it slightly because we're fine with the top level having attributes :

is_expression2 <- function(x) {
  if (rlang::is_syntactic_literal(x) || rlang::is_symbol(x)) return(TRUE)
  if(!rlang::is_call(x)) return(FALSE)
  all(vapply(x, function(x) is.null(attributes(x)) && is_expression2(x), logical(1)))
}

It works :) :

library(constructive)
x <- quote(a(1)(2))
attr(x[[1]], "foo") <- "bar"
construct(x)
#> as.call(list(
#>   quote(a(1)) |>
#>     structure(foo = "bar"),
#>   2
#> ))

y <- quote(a(1))
y[[1]] <- mean
construct(y)
#> as.call(list(
#>   as.function(alist(x = , ... = , UseMethod("mean")), envir = .BaseNamespaceEnv),
#>   1
#> ))

construct(y, data = list(mean = mean))
#> as.call(list(mean, 1))

from constructive.

moodymudskipper avatar moodymudskipper commented on July 2, 2024

Solved in 3b675b9 and improved secret and attribute handling with 593558b

from constructive.

github-actions avatar github-actions commented on July 2, 2024

This old thread has been automatically locked. If you think you have found something related to this, please open a new issue and link to this old issue if necessary.

from constructive.

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