Comments (4)
Would be miraculously a 3 lines fix with rlang::is_expression()
if it returned FALSE
when the call hides attributes. See r-lib/rlang#1475
We might have to reprogram is_expression()
, the logic doesn't seem extractable easily.
Or we implement another recursive logic but it won't be half as pretty.
from constructive.
There seems to be a logic in rlang to avoid recursion, probably for some stack issues since they stop at 100 anyway. But for our use case this should do it:
is_expression2 <- function(x) {
if(!is.null(attributes(x))) return(FALSE)
if (rlang::is_syntactic_literal(x) || rlang::is_symbol(x)) return(TRUE)
if(!rlang::is_call(x)) return(FALSE)
all(vapply(x, is_expression2, logical(1)))
}
And we tweak it slightly because we're fine with the top level having attributes :
is_expression2 <- function(x) {
if (rlang::is_syntactic_literal(x) || rlang::is_symbol(x)) return(TRUE)
if(!rlang::is_call(x)) return(FALSE)
all(vapply(x, function(x) is.null(attributes(x)) && is_expression2(x), logical(1)))
}
It works :) :
library(constructive)
x <- quote(a(1)(2))
attr(x[[1]], "foo") <- "bar"
construct(x)
#> as.call(list(
#> quote(a(1)) |>
#> structure(foo = "bar"),
#> 2
#> ))
y <- quote(a(1))
y[[1]] <- mean
construct(y)
#> as.call(list(
#> as.function(alist(x = , ... = , UseMethod("mean")), envir = .BaseNamespaceEnv),
#> 1
#> ))
construct(y, data = list(mean = mean))
#> as.call(list(mean, 1))
from constructive.
Solved in 3b675b9 and improved secret and attribute handling with 593558b
from constructive.
This old thread has been automatically locked. If you think you have found something related to this, please open a new issue and link to this old issue if necessary.
from constructive.
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from constructive.