Comments (7)
di
commented on September 15, 2024
1
Yes.
from flask-accept.
di
commented on September 15, 2024
Hi, can you provide a minimal example?
from flask-accept.
TapanHP1995
commented on September 15, 2024
Here is where I created a function and defined the @accept decorator
@accept("application/json")
@demo_bp.route('/server_check', methods=['GET'])
def check_server_health():
"""
This method is just for checking server health and endpoints working
:return: A simple string message
"""
return send_success_response(message="Server is working OK")
When I can this endpoint from postman or cUrl with let's say "text/html" then It will send me error in HTML format, as I think you have raised NotAcceptable exception in code
So it will show,
<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 3.2 Final//EN">
<title>406 Not Acceptable</title>
<h1>Not Acceptable</h1>
<p>The resource identified by the request is only capable of generating response entities which have content characteristics not acceptable according to the accept headers sent in the request. Supported entities are: application/json</p>
Now If I want the response in JSON in this case as I am using it with APIs so front end will expect to be it in Json with maybe a response like this one.
{error: "The resource identified by the request is only capable of generating response entities which have content characteristics not acceptable according to the accept headers sent in the request. Supported entities are: application/json"}
Can I do it, or it will be always in HTML?
from flask-accept.
di
commented on September 15, 2024
OK, so here's an actual minimal example:
from flask import Flask, jsonify
from flask_accept import accept
app = Flask(__name__)
@app.route('/', methods=['GET'])
@accept("application/json")
def check():
return "Server is working OK"
app.run('0.0.0.0', 8080, debug=True)If I run this locally, I get:
$ curl localhost:8080
<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 3.2 Final//EN">
<title>406 Not Acceptable</title>
<h1>Not Acceptable</h1>
<p>The resource identified by the request is only capable of generating response entities which have content characteristics not acceptable according to the accept headers sent in the request. Supported entities are: application/json</p>
To make that a JSON response instead, you need to provide a custom error handler, for example:
from flask import jsonify
@app.errorhandler(406)
def not_acceptable(e):
return jsonify({'error': 'Not Acceptable'}), 406Which will give you:
$ curl localhost:8080
{
"error": "Not Acceptable"
}
from flask-accept.
TapanHP1995
commented on September 15, 2024
So How would the library fit in this case? So in your example, the accept decorator is not added. So I am confused about how it will work? so let's say using the library instead of sending the HTML response. What I intended to do is
{"message": "The resource identified by the request is only capable of generating response entities which have content characteristics not acceptable according to the accept headers sent in the request. Supported entities are: application/json"}
using the accept library itself and not adding one more error handler, In your JSON example you have not used the library at all
from flask-accept.
di
commented on September 15, 2024
I think you need to take a closer look at the example 🙂
from flask-accept.
TapanHP1995
commented on September 15, 2024
okay so If I override the 406 at app handler level then accept would automatically follow what that function is sending, right?
from flask-accept.
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from flask-accept.