Comments (1)
UPDATE
In the end I solved it by changing the last else block:
else:
start_mask = (1 << (8 - start_bit)) - 1
end_mask = ~((1 << (8 - end_bit - 1)) - 1)
screen[start_byte] |= start_mask
screen[end_byte] = int('11111111', base=2)
screen[end_byte] &= end_mask
I looked back at the first challenge (bits) in bit_manipulation series. I set the last bit to all 1s, then used the method from the clear_bits_index_to_lsb method in the bits challenge.
I have a couple of questions about this.
- Setting all bits in a byte is done using
int('11111111', base=2)
. This could just be done by setting it to equal255
. What is the reason to use the much longer way? - Is there some mask that can be used to set all bits from MSB to an index? This would prevent the need to first set all bits then clear the bits to the right of the index.
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