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mccolljr avatar mccolljr commented on September 18, 2024

time.Sleep blocks the calling groutine within the go context. It is similar to thread.Sleep in other languages, so from the perspective of goja, your delay function is a synchronous function that takes one second to return. Instead, you would need to return a Promise which is resolved after 1 second.

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didi-stwn avatar didi-stwn commented on September 18, 2024

Hi @mccolljr thanks for the reply.

I change delay function into this (HTTP Request using resty package)

vm.Set("delay", func(id string) string {
  // Create a new Resty client
  client := resty.New()

  // Initialize a new request
  request := client.R()

  // request to public API
  resp, err := request.Get("https://jsonplaceholder.typicode.com/todos/" + id)
  if err != nil {
	  return err.Error()
  }

  return string(resp.Body())
})

But I still got same result (synchronous function). I think this is because vm.Set define sync function not async function

Can I define async function using vm.Set or other method?

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mccolljr avatar mccolljr commented on September 18, 2024

In Javascript, including in the goja engine, an "async function" is any function that returns a Promise value. Neither of your functions return a Promise value. The goja runtime is treating both functions as synchronous functions because they are.

If you want an async function, you will have to have a look at Runtime.NewPromise.

You will need to follow the example from the documents. You need an event loop, and you need to spawn a separate goroutine to handle the blocking work (like sending an http request or sleeping), and arrange for this goroutine to resolve the Promise value. Please note that the documentation for this function states that you cannot just call resolve or reject from another goroutine. You need an event loop, and you have to schedule the call to resolve to happen on that event loop. Then, without waiting for this goroutine to finish, you need to return the Promise object from your function. Only then will goja be able to understand that your function is async.

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didi-stwn avatar didi-stwn commented on September 18, 2024

Thank you @mccolljr I will try it

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