便捷的时间工具 | Go 语言编程之旅 about go-programming-tour-book-comments HOT 11 OPEN

cmd/time.go中calculateTimeCmd的space=1的分支layout格式没有秒

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1.3.3.2 time calc 子命令 中，利用冒号:来做分隔符会更妥当，使用空格作为分隔符会造成bug

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我直接clone下来项目但是测试的时候总是会有异常，输出结果: 1970-01-01 08:05, 300，一直报的是这个

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space := strings.Count(calculateTime, " ")中把" "改成" "就可以了

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改成":"

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好的，我按照你说的将空格删掉了之后就成功了，谢谢！

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输出异常的真正原因是，space为1的时候，layout写错了。
作者写成了layout = "2006-01-02 15:04"，正确写法应该是layout = "2006-01-02 15:04:05"

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您好 1.3.3.2 time calc 子命令 处好像有bug

if space == 0 {
layout = "2006-01-02"
}
if space == 1 {
layout = "2006-01-02 15:04"
}

命令行中 2029-09-04 12:02:33 输入的space为1，但是匹配到的layout是 2006-01-02 15:04，在秒数上是对应不上的，因此会出现得出的结果为：1970-01-01 08:05。 按照代码贴上去发现了这个问题

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space := strings.Count(calcTime, " ")
if space == 0 {
layout = "2006-01-02"
}
if space == 1 {
layout = "2006-01-02 15:04"
}
如果输入时候多输入了空格会发生不可预测的问题，判断冒号":"可能会更好一些

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			space := strings.Count(calculateTime, " ")
			if space == 0 {
				layout = "2006-01-02"
			} else if space == 1 {
				switch strings.Count(calculateTime, ":") {
				case 0:
					layout = "2006-01-02 15"
				case 1:
					layout = "2006-01-02 15:04"
				}
			}

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我觉得这样判断更合理，空格数量决定年月日后面有没有跟上时分秒，冒号数量决定时分秒这三个字段输入了几个：

space := strings.Count(calculateTime, " ")
if space == 0 {
	layout = "2006-01-02"
} else {
	switch strings.Count(calculateTime, ":") {
	case 0:
		layout = "2006-01-02 15"
	case 1:
		layout = "2006-01-02 15:04"
	}
}

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