It could be done like this: <div class="highlight highlight-source-python notransl

Feature request: Support Microchip HEX format about bincopy HOT 3 CLOSED

eerimoq commented on July 17, 2024

Feature request: Support Microchip HEX format

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Comments (3)

eerimoq commented on July 17, 2024

Can the format be handed without a flag to Bincopy? I prefer to have format logic in add*() methods.

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bessman commented on July 17, 2024

It could be done like this:

def add_microchip_hex(self, records, overwrite=False):
    self.word_size_bytes = 1
    self.add_ihex(records, overwrite)
    self.word_size_bytes = 2
    self.segments.word_size_bytes = 2
    for segment in self.segments:
        segment.word_size_bytes = 2

def add_microchip_hex_file(self, filename, overwrite=False):
    with open(filename, 'r') as fin:
        self.add_microchip_hex(fin.read(), overwrite)

However, since Microchip's format is indistinguishable¹² from Intel, users would have to directly call add_microchip_hex_file:

import bincopy
# binfile = BinFile("microchip.hex")  # Won't work.
binfile = BinFile()
binfile.add_microchip_hex_file("microchip.hex")

In practice, I think every fourth byte in a Microchip HEX is guaranteed to be zero (even though the example given in Microchip's format definition contradicts this), which could in theory be used to determine if a file is a normal Intel HEX or a Microchip HEX. Seems a little fragile to rely on that, since it's not explicit in the format definition. ↩
Scratch that, that is only the case for 16-bit word / 24-bit instruction. For PIC18 (8-bit word / 16-bit instruction) there is no such pattern. I think the formats are truly indistinguishable. ↩

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eerimoq commented on July 17, 2024

Looks like a good plan.

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