Return the percentage the color covers in the image about color-thief-py HOT 6 OPEN

If @jyotiska, @amitmadan18, or anybody else needs this information, I figured it out with the help of an issue at the original color-thief repo.

Change the palette method at line 356 in colorthief.py from:

def palette(self):
    return self.vboxes.map(lambda x: x['color'])

to:

def palette(self):
    total = sum(self.vboxes.map(lambda x: x['vbox'].count))
    return self.vboxes.map(lambda x: x['color'] + (x['vbox'].count, total, int(x['vbox'].count / float(total) * 100)))

I simply added additional members to each RGB tuple:

• The pixel count of each color
• The total sum of all pixels, which will always be the same
• The integer percentage of each color

Now palette = color_thief.get_palette(color_count=3) will return something like [(236, 70, 70, 1875, 1000, 18), (4, 4, 252, 625, 1000, 6), (4, 4, 4, 7500, 1000, 75)], giving 18%, 6%, and 75%. Tweak to your liking. Fork the repo to make your change.

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I'm also interested in this data. Is there another library that can do it?

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I am also interested in the same data @jyotiska @richardcornish
Please let me know if it's possible

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Correct. If I remember correctly, I also came up with my own hack something like this to print out the histogram.

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Thanks. Even I had came up with the same solution :)
On 14 Jun 2016 11:34, "Jyotiska Khasnabish" [email protected]
wrote:

Correct. If I remember correctly, I also came up with my own hack
something like this to print out the histogram.

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Is is comming to the main package or do I need to make a fork myself?

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