Attributes to serialize a dictionnary about typescript-json-serializer HOT 4 CLOSED

Hi, let me check.

from typescript-json-serializer.

If that is simpler, what about this with a Map instead ?
@JsonProperty( ??)
public someDic: Map<string,ColumnReference>;

from typescript-json-serializer.

I have this ugly workaround

@JsonProperty({ onDeserialize: deserMe }) //, onSerialize: serMe })
public someDic: { [id: string]: ColumnReference } = {};

function deserMe(dic:{ [id: string]: ColumnReference })
{
let res:{ [id: string]: ColumnReference }={};
Object.entries(dic).forEach(([K, V]) => res[K]= deserialize(V, ColumnReference));
return res;
}

I tried to get deserMe generic with this in mind:
function deserMe(dic:{ [id: string]: T })
{
let res:{ [id: string]: T }={};
Object.entries(dic).forEach(([K, V]) => res[K]= deserialize(V, T));
return res;
}

but I am not good enough in typescript to get it to work.
I saw this : export declare function deserialize(json: object, type: new (...params: Array) => T): T;
I cannot understand what does this type: new (...params: Array) => T

from typescript-json-serializer.

Hi, sorry to be late.

I added a new option called isDictionary that you must set to true and you need to specify the focused class if needed.

@JsonProperty({ type: ColumnReference, isDictionary: true })
public someDic: { [id: string]: ColumnReference } = {};

I let you test the new version 2.4.0 😊

PS: note that the ES6 Map object are not serializable (I mean using JSON.stringify function) so I can't manage this kind of data directly.

from typescript-json-serializer.