Comments (1)
example detailing what i cannot figure out how to do
aka, streaming the "result" field of a jsonrpc response.
sometimes these responses can tens of GBS
package main
import (
"bytes"
"encoding/json"
"log"
"github.com/go-faster/jx"
)
type v struct {
V string `json:"v"`
}
func main() {
existingPackage()
withIoWriter()
}
func existingPackage() {
val := &v{V: "bar"}
out := new(bytes.Buffer)
e := jx.NewStreamingEncoder(out, 4096)
// CURRENT
e.Obj(func(e *jx.Encoder) {
e.Field("jsonrpc", func(e *jx.Encoder) { e.Str("2.0") })
e.Field("method", func(e *jx.Encoder) { e.Str("method") })
e.Field("result", func(e *jx.Encoder) {
// NOTE: in order to encode val, we must first buffer the ENTIRE message
raw, _ := json.Marshal(val)
// and pass that in
e.Raw(raw)
})
})
e.Close()
ans := out.String()
log.Println(ans)
out.Truncate(0)
}
func withIoWriter() {
val := &v{V: "bar"}
out := new(bytes.Buffer)
out.WriteString(`{`)
out.WriteString(`"jsonrpc":"2.0",`)
out.WriteString(`"method":"`)
out.WriteString(`method`)
out.WriteString(`",`)
out.WriteString(`"result":`)
// importantly, this can be streamed directly to network, instead of buffering. also, it adds a newline because it's an encoder, but that is a separate issue :)
json.NewEncoder(out).Encode(val)
out.WriteString(`}`)
ans := out.String()
log.Println(ans)
out.Truncate(0)
}
from jx.
Related Issues (10)
- docs: no pkg.go.dev reference is available HOT 1
- test: cleanup
- Use table tests, generate cases for in-memory and streaming decoding
- perf: get rid of allocation in float decoding slow path
- perf: research performance impact of bytesets HOT 1
- idea: provide fast encoders and decoders for popular types
- feat: streaming encoding
- feat: object iterator
- feat: speedup float skip
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from jx.