Accessing a class attribute that is a wrapt wrapped function will try and bind the function. about wrapt HOT 4 OPEN

By the way, I really appreciate the work that went into this. wrapt has been invaluable for building enact. We use it for wrapping python code to perform automatic telemetry and replays, e.g., to search the space of program executions of a non-deterministic python program, which comes in handy in the context of working with LLMs.

from wrapt.

Can you explain better why it is a problem for you and what you are trying to do?

Since you are using () and triggering a call the behaviour is as I would expect, including the error.

If you want the wrapped function to be tolerant of bogus arguments you should use:

@passthrough
def foo(*args, **kwargs):
  print('foo')

or filter them out in passthrough decorator wrapper function when calling the wrapped function.

@wrapt.decorator
def passthrough(wrapped, instance, args, kwargs):
  # Ignore all arguments.
  return wrapped()

from wrapt.

It's not the behavior that I expected, since I assumed that a decorator such as passthrough would not change the semantics of the function it wraps. My use case is related to telemetry, so maybe let's take logging as an example.

import logging

@wrapt.decorator
def log_calls(wrapped, instance, args, kwargs):
  logging.info('%s called with %s / %s', wrapped, args, kwargs)  
  return wrapped(*args, **kwargs)

I would have assumed that the intended contract is that annotating any function in a python program with log_calls does not change the behavior of the program, except for the additional logging.

It appears this is not the case.

E.g.:

def foo():
  print('foo')

def my_code(fun):
  class A:
    _fun = fun
  A._fun()

my_code(foo)  # succeeds for unwrapped functio
my_code(log_calls(foo))  # fails for wrapped function

from wrapt.

Okay, am overlooking that you pointed out error arises from internal to wrapt and not when called by the wrapper.

Let me think about it and I'll do some tests.

from wrapt.