Comments (2)
KDreamelf
commented on July 18, 2024
又一轮测试，这次彻底爆了（攻击方法：手机自带滤镜）。
加密图：
攻击图：
解码：�Fu�$��=�m��P|�f_I,OH
v9��G�/�V
M��"��21���ØS�����{7/��;�u�*蹏��
简单的说，目前的鲁棒性只能防不小心损毁，防不了故意移除。所以不能用作保护创作者版权。
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liduang
commented on July 18, 2024
是的，我测试发现加些滤镜色彩变换，就解不出来了。缩放也是这样
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Related Issues (20)
- 没能抵挡多少个攻击，你文档怎么瞎写？
- 没能抵挡多少个攻击，你文档怎么瞎写？ HOT 3
- 剪切攻击 + 缩放攻击 + 不知道攻击参数 能否在没有原始的加完水印后的图的时候提取参数 HOT 4
- 解码需要提供wm_shape这个参数，正确的使用方法是怎样的？谢谢 HOT 5
- 求算法论文分享 HOT 1
- 图片过大 添加水印 提示warning: iCCP: known incorrect sRGB profile
- extract ERROR HOT 2
- Taking a screenshot of a picture with a watermark, garbled characters appear when extracting it. HOT 4
- Significatelly drops image quality HOT 2
- 尝试编辑图片之后无法正确解码
- non-hexadecimal number found in fromhex() arg at position 11
- 添加水印之后，图片质量会变差，有办法解决吗 HOT 2
- decode error WaterMark.__init__() got an unexpected keyword argument 'wm_shape'
- 补白边和去除白边的代码会直接卡死
- 缩放后无法提取水印
- 水印后图像质量问题无法解决 HOT 1
- 执行后未生成嵌入水印后的图片 HOT 3
- 展示的例子中的图片，无法承载解压出的二维码
- 用相同方法在matlab中实现，发现传递rawdata总是会有bit位的错误，为什么楼主的不会有错误？
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