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wwwfeng avatar wwwfeng commented on June 3, 2024

I have the following code, but if multiple instances of asynq are started, the scheduled task may be registered to Redis repeatedly. How to avoid this?

....
task := asynq.NewTask(pb.SchedulerType_STAT_CAR_UPTIME.String(), nil)
entryID, err := l.svcCtx.Scheduler.Register(crontab, task)
....

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aaps3579 avatar aaps3579 commented on June 3, 2024

@wwwfeng Yes. If multiple instances of scheduler are started, task will be scheduled multiple times.
Refer to this thread #395 for solution.

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wwwfeng avatar wwwfeng commented on June 3, 2024

@wwwfeng Yes. If multiple instances of scheduler are started, task will be scheduled multiple times. Refer to this thread #395 for solution.

Thanks for your reply. I checked the documentation and used asynq.TaskID and asynq.Retention, and it seems to be effective. Does this mean that the same scheduled task will only be written once within the time set by asynq.Retention?

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aaps3579 avatar aaps3579 commented on June 3, 2024

Retention time dictates for how much long task is gonna stay in the system. And any task enqueued with same taskID will give asynq.ErrTaskIDConflict error.

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wwwfeng avatar wwwfeng commented on June 3, 2024

Retention time dictates for how much long task is gonna stay in the system. And any task enqueued with same taskID will give asynq.ErrTaskIDConflict error.

Thank you so much for your response.I understand now.

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