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michalCapo avatar michalCapo commented on September 27, 2024 1
typeof user.TYPE

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michalCapo avatar michalCapo commented on September 27, 2024 1
import { number, object, optional, string } from "superstruct";

const user = object({
    id: number(),
    name: string(),
    some: optional(string()),
});

console.log(user.schema.name.validate(undefined)[0] == null) // false
console.log(user.schema.some.validate(undefined)[0] == null) // true

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hemedani avatar hemedani commented on September 27, 2024

This task was not very difficult. By writing a few helper functions, I was able to get the output I wanted. However, there is a serious problem. In Runtime, I did not find anything related to a field being optional. Actually, I have written a framework called Lesan with Superstruct. You can see the code I wrote to create the types here:

https://github.com/MiaadTeam/lesan/blob/main/src/types/generateTypesFromStruct.ts

Of course, this code has not been fully written yet.

But the problem is when we create an object with the following two fields:

object({
    optionalName: optional(string()),
    name: string(),
});

At runtime, we get something like this:

{
	"type": "object",
	"schema": {
		"optionalName": {
			"type": "string",
			"schema": null,
		},
		"name": {
			"type": "string",
			"schema": null,
		},
	},
}

I don't see anything related to the optionalName field being optional! While, we have put it in the optional(string()) function.
How should I know at runtime if a field is optional?
Finally, the type I create for the above struct is as follows:

{
	optionalName: string;
	name: string;
}

which I want to create it like this:

{
	optionalName?: string;
	name: string;
}

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hemedani avatar hemedani commented on September 27, 2024

Completed, but how?
Please give a brief explanation.
thanks a lot

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