== Operator for Contact is broken about flutter_contacts HOT 5 CLOSED

@lukasgit if you could help me with this that would be great cuz the current solution (converting to json, then comparing that) is very slow in comparison to comparing the objects directly

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After further inspection things seem to fail here specifically

DeepCollectionEquality.unordered().equals

Im going to try to convert them to sets and then simply doing a .contains

from flutter_contacts.

Hi @b-cancel we are swamped right now and with limited resources available at the moment. Please feel free to contribute updates and improvements via PR.

Also, major code changes were recently pushed. You will want to grab the latest code. Thanks!

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@lukasgit I am swapped too... but I'll put this here for when I have time...

So this is how I solved it
Not sure if its the best way (which is why I don't do a PR) but it works

  && itemsEqual(
    castToList(c1.phones), 
    castToList(c2.phones),
  )
  && itemsEqual(
    castToList(c1.emails), 
    castToList(c2.emails),
  )
  && postalAddressesEqual(
    castToList(c1.postalAddresses), 
    castToList(c2.postalAddresses),
  )

Using The Functions Below

//-----For Both

List castToList(var list){
  if(list.runtimeType == new List().runtimeType) return list;
  else return list.toList();
}

//-----For Items

bool itemsEqual(List<Item> l1, List<Item> l2){
  if(l1.length != l2.length) return false;
  else{
    Set<Item> s1 = l1.toSet();
    for(int i = 0; i < l2.length; i++){
      if(s1.contains(l2[i]) == false) return false;
    }
    return true;
  }
}

//-----For Postal Addressses

bool postalAddressesEqual(List<PostalAddress> l1, List<PostalAddress> l2){
  if(l1.length != l2.length) return false;
  else{
    Set<PostalAddress> s1 = l1.toSet();
    for(int i = 0; i < l2.length; i++){
      if(s1.contains(l2[i]) == false) return false;
    }
    return true;
  }
}

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This issue has been automatically marked as stale because it has not had recent activity. It will be closed if no further activity occurs. Thank you for your contributions.

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