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Comments (6)

allensanborn avatar allensanborn commented on September 13, 2024

The best example of the problem is in the bottom right where there are many ways to submit the item to the customer for review. There are lots of in out edges and there is no way to tell what's tied to what. Which state and transition will lead to state 'State_CustomerReview_None'?

from automatonymous.

allensanborn avatar allensanborn commented on September 13, 2024

What I would like it to look like is this minus the ids I added to the events to make them unique. btw i just generated the code with a spreadsheet since this is still all in flux
state

from automatonymous.

phatboyg avatar phatboyg commented on September 13, 2024

I've noticed some strange issues for sure, particularly in how multiple edges are created between nodes. I'll take a look at your better graph and see what I can do with the next update.

from automatonymous.

allensanborn avatar allensanborn commented on September 13, 2024

Thanks. I started looking through the graph visualizer and quickgraph/graphviz but it was a lot to take in. Hopefully once I get the code working I'll be able to circle back around and give you some more info... stupid deadlines.

from automatonymous.

allensanborn avatar allensanborn commented on September 13, 2024

http://www.graphviz.org/content/fsm

Here's what I was looking for from the visualizer. The events should all be added as labels instead of states.

http://www.graphviz.org/Gallery/directed/fsm.gv.txt
digraph finite_state_machine {
rankdir=LR;
size="8,5"
node [shape = doublecircle]; LR_0 LR_3 LR_4 LR_8;
node [shape = circle];
LR_0 -> LR_2 [ label = "SS(B)" ];
LR_0 -> LR_1 [ label = "SS(S)" ];
LR_1 -> LR_3 [ label = "S($end)" ];
LR_2 -> LR_6 [ label = "SS(b)" ];
LR_2 -> LR_5 [ label = "SS(a)" ];
LR_2 -> LR_4 [ label = "S(A)" ];
LR_5 -> LR_7 [ label = "S(b)" ];
LR_5 -> LR_5 [ label = "S(a)" ];
LR_6 -> LR_6 [ label = "S(b)" ];
LR_6 -> LR_5 [ label = "S(a)" ];
LR_7 -> LR_8 [ label = "S(b)" ];
LR_7 -> LR_5 [ label = "S(a)" ];
LR_8 -> LR_6 [ label = "S(b)" ];
LR_8 -> LR_5 [ label = "S(a)" ];
}

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phatboyg avatar phatboyg commented on September 13, 2024

I just fixed this in the mt3 branch, which is going to released as yet another prerelease version shortly (3.0.2)

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