The type of the return value is omitted. about typescript HOT 5 CLOSED

If you want a type that means "any possible value" but is actually typesafe, you should use unknown instead of any. any basically means "don't typecheck this value in any context"

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Indeed. See https://www.typescriptlang.org/docs/handbook/basic-types.html#any

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Sure, I understand that. The 'any' type is not the problem I am bringing to your attention.
Of course, I could provide the type number instead of 'any' and it would work as it should, but the behavior I encountered allows to break the contract.
The problem is that a variable that has a type specified as number[] and a function that has a declared return value also as number[] pass the string 'x' to value with type number[].

If this is intentional, I have a very hard time accepting it.

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Your example errors unless you use any. The point of any is to not generate errors. It couldn't be more intentional.

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However, I thought that:

• 'any' allows the function to accept any type of a given parameter
• return number[] ensures that regardless of the parameters the function takes, only number values will be provided in the returned array.

Thank you for your answers and patience.
Now I am aware that this can happen, although it is a bit unintuitive. I'll keep an eye out for this in my code.
Regards!

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