Deion: Tried with Zotero (Oauth v1) but failed with error:

Does not work with Zotero Oauth about oauthswift HOT 3 CLOSED

hassanzadeh commented on June 2, 2024

Does not work with Zotero Oauth

from oauthswift.

Comments (3)

hassanzadeh commented on June 2, 2024

Here is my code:
`func authenticateWithZotero() {
let oauthswift = OAuth1Swift(
consumerKey: "xxx",
consumerSecret: "zzzz",
requestTokenUrl: "https://www.zotero.org/oauth/request",
authorizeUrl: "https://www.zotero.org/oauth/authorize",
accessTokenUrl: "https://www.zotero.org/oauth/access"
)

                    oauthswift.authorize(
                        withCallbackURL: URL(string: "scholarsync://zotero")!) { result in
                            switch result {
                            case .success(let (credential, _, _)):
                                print(credential.oauthToken)
                                // Save these tokens; they are needed for accessing the API
                            case .failure(let error):
                                print(error.localizedDescription)
                            }
                        }
                }`

from oauthswift.

phimage commented on June 2, 2024

please use correctly markdown

let oauthswift = OAuth1Swift is bad, you do not follow readme and demo code
that cause
-10 > https://github.com/OAuthSwift/OAuthSwift/blob/master/Sources/OAuthSwiftError.swift#L58

from oauthswift.

hassanzadeh commented on June 2, 2024

Thanks for your response,
I tested it, it gives me the oauth_token but Not the access_token, is there a specific function I should call to get the access token?

from oauthswift.

Does not work with Zotero Oauth about oauthswift HOT 3 CLOSED

Comments (3)

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