Comments (1)
#콜라츠 추측
def solution(num):
answer = 0
while True:
if num == 1:
return answer
elif answer == 500: #500회 일때 -1 리턴
return -1
if num % 2 == 0:
num = num / 2
elif num % 2 == 1:
num = num * 3 + 1
answer += 1
return answer
print(solution(6)) #8
print(solution(16)) #4
print(solution(626331)) #-1
#정수 N개로 이루어진 수열 A와 정수 X가 주어진다. 이때, A에서 X보다 작은 수를 모두 출력하는 프로그램을 작성하시오.
N, X = map(int, input().split())
A = list(map(int, input().split()))
for i in range(N):
if A[i] < X:
print(A[i], end = " ")
from 2021-spring-python-tutoring.
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from 2021-spring-python-tutoring.