Comments (5)
The int
version working seems a bit odd because 4
is being "replaced" by [4]
I did notice that forcing the default value is possible:
df_str.select(
pl.col("a").list.eval(
pl.element().replace({"1": ["11", "111"], "2": ["22"]}, default=pl.concat_list(pl.element()))
)
)
# shape: (1, 1)
# ┌────────────────────────────────┐
# │ a │
# │ --- │
# │ list[list[str]] │
# ╞════════════════════════════════╡
# │ [["11", "111"], ["22"], ["4"]] │
# └────────────────────────────────┘
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ahh i figured that happens to force a consistent datatype. Neat workaround with the default though!
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I too am hoping for this to be resolved!
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@ThomasMAhern What do you need resolved?
It seems that both examples should raise here and the fact that the int case works is a "bug"?
EDIT: Ah, the return_dtype
docs say: "the data type is determined automatically based on the other inputs" - so perhaps I am mistaken.
Just experimenting further, something else seems broken:
df_int.with_columns(
a1 = pl.col("a").list.eval(pl.element().replace("1", [["a", "b"]]))
)
# shape: (1, 2)
# ┌───────────┬────────────────────────────┐
# │ a ┆ a1 │
# │ --- ┆ --- │
# │ list[i64] ┆ list[list[str]] │
# ╞═══════════╪════════════════════════════╡
# │ [1, 2, 4] ┆ [["a", "b"], ["2"], ["4"]] │
# └───────────┴────────────────────────────┘
1
is being cast to "1"
then the replace succeeds?
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It seems I'm able to get the expected output if I specify return_dtype=pl.List(pl.String)
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