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github-actions avatar github-actions commented on July 23, 2024

This issue is stale because it has been open for 14 days with no activity.

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amit-sharma avatar amit-sharma commented on July 23, 2024

The error you are seeing is unrelated to the linked issue.
In your case, the only valid backdoor set is $[U, Z]$, but since U is unobserved, identify_effect method returns that backdoor identification is not possible.

Note that graph argument takes precedence in CausalModel. So if you only want to condition on Z, you have can do so if by initializng CausalModel directly, without the graph.

model = CausalModel(
data=df,
treatment=['X'],
outcome=['Y'],
common_causes=['Z']
)

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asha24choudhary avatar asha24choudhary commented on July 23, 2024

Thank you for your reply @amit-sharma, I reason why i linked the previous issue is because I wanted to include unobserved confounder. But don't you think I should include the graph which contains the info about the unobserved confounder 'U', which is also done in the issue I linked?

I was assuming that in order to have unobserved confounder, I should include it in the graph which is used while creating the model and exclude it in the dataset.

Yes if I exclude the graph while modelling, then the valid backdoor path includes Z. However, my question to u now is that should I not include the graph & why, because don't you think if I do so then I lose the info about the unobserved confounder in the model, of course it is still present in the data?

Would be really helpful if you could explain a bit more in detail.

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github-actions avatar github-actions commented on July 23, 2024

This issue is stale because it has been open for 14 days with no activity.

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github-actions avatar github-actions commented on July 23, 2024

This issue was closed because it has been inactive for 7 days since being marked as stale.

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