Comments (2)
Great catch! Symbols() are inherently non-enumerable. Do you have a solution in mind? If not I can look into fixing
from types.
While looking into this, I found out it's worse than just symbols. The current typing for toPairs
includes any non-enumerable property in its output, including class methods!
Check out this simple instance of a class put through R.toPairs
Now let's put the same code into typescript/play
Simplified here, you get this
import * as R from 'ramda';
class Point {
public x: number;
public y: number;
constructor(x: number, y: number) {
this.x = x;
this.y = y;
}
map(fn: (a: number) => number) {
return new Point(fn(this.x), fn(this.y));
}
}
const point = new Point(3, 2);
const asPairs = R.toPairs(point);
// ^? ["x", number] | ["y", number] | ["map", (fn: (a: number) => number) => Point]
// but the value you get is `[["x", 3], ["y", 4]]`
What this means is we can never use keyof
to determine what should be part of the output array of key/value pairs
Because you also would have map
if you use a function to create and object literal:
const makePoint = (x, y) => ({
x,
y,
map: fn => makePoint(fn(x), fn(y))
});
const point2 = makePoint(3, 2);
const asPairs2 = R.toPairs(point2);
// ^? ["x", number] | ["y", number] | ["map", (fn: (a: number) => number) => Point]
// but the value you get is `[["x", 3], ["y", 4], ["map", null]]`
I've always thought that the way Object.entires was typed was just due to very old typescript, before it had the ability to be more specific
entries<T>(o: { [s: string]: T; } | ArrayLike<T>): [string, T][];
But I understand now that it's due to how keyof
does not descriminate against non-enumerables and non-own-properties
I'm thinking that the types for toPairs
and fromPairs
just needs to be typed exactly like Object.entries
and Object.fromEntries
, respectively.
Same with Object.keys
and R.keys
, Object.values
and R.values
, etc
Shitty thing is this is going to be a breaking change
from types.
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from types.