Comments (3)
Perhaps, an alternative could be:
// enumFromThenTo :: Int -> Int -> Int -> [Int]
const enumFromThenTo1 = m =>
// Integer values enumerated from m to n
// with a step defined by (nxt - m).
nxt => n => {
const d = nxt - m;
return Array.from({
length: Math.floor(d/n) + 1
}, (_, i) => m + (n * i));
};
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You were expecting a different return value ?
It should evaluate to the same as [1,11..2] in Haskell, i.e. [1]
but I may be missing your point ?
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I apologise ! I wonder why I was so sure about the purpose of the last argument. I thought like it was a step. So, I expected:
[1,3,5,7,9,11]
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