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Comments (6)

GoogleCodeExporter avatar GoogleCodeExporter commented on June 25, 2024
Make sure your User class implement JSONAware:

class User implements JSONAware{
  ...
}

Original comment by [email protected] on 23 Apr 2009 at 4:10

from json-simple.

GoogleCodeExporter avatar GoogleCodeExporter commented on June 25, 2024
Yes I create interface JSONAware in same package and implement JSONAware. Look 
at my
code : http://stargate.cnl.tuke.sk/~maly/simple

Original comment by [email protected] on 23 Apr 2009 at 6:14

from json-simple.

GoogleCodeExporter avatar GoogleCodeExporter commented on June 25, 2024
I looked into your code. You should do 2 things below:
1. Use JSONAware(org.json.simple.JSONAware) from JSON.simple instead of 
creating your
own;

2. class User should implement org.json.simple.JSONAware:
class User implements org.json.simple.JSONAware {
  ...
}

Original comment by [email protected] on 23 Apr 2009 at 10:04

from json-simple.

GoogleCodeExporter avatar GoogleCodeExporter commented on June 25, 2024
Ok, I pass interface org.json.simple.JSONAware into package org.json.simple.* 
but
error always exist. I am dispairing. I give on server test web app which 
content only
this trouble> http://stargate.cnl.tuke.sk/~maly/jquery_1/  

Original comment by [email protected] on 23 Apr 2009 at 6:13

from json-simple.

GoogleCodeExporter avatar GoogleCodeExporter commented on June 25, 2024
Your resultJ.java looks good. Please make sure the compiled resultJ.class is up 
to
date and no old version is cached in you app classpath.

Original comment by [email protected] on 27 Apr 2009 at 4:42

from json-simple.

GoogleCodeExporter avatar GoogleCodeExporter commented on June 25, 2024

Original comment by [email protected] on 28 Apr 2009 at 2:59

  • Changed state: Invalid

from json-simple.

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