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rusty1s avatar rusty1s commented on June 18, 2024 1

It looks like what you wanna do is take the intersection of two sparse matrices, where for duplicated values, you wanna decide for the value in y. This is generally possible (although not through torch.where syntax):

row, col, _ = x.coo()
flat_index_x = row * x.size(1) + col

row, col, value = y.coo()
flat_index_y = row * y.size(1) + col

mask = torch.isin(x, y)

# filter y by intersection:
y = SparseTensor(row=row[mask], col=col[mask], value=value[mask])

from pytorch_sparse.

rusty1s avatar rusty1s commented on June 18, 2024

Sorry, can you clarify what you mean exactly?

from pytorch_sparse.

KukumavMozolo avatar KukumavMozolo commented on June 18, 2024

Let me try:
Let x be a sparse tensor, and f(x) = y, some transformation that potentially makes y less sparse,
then i want to ensure that wherever x was 0 y is also 0.
with a dense tensor it can be done like this:

y = torch.where(x==0,torch.tensor([0]),y)

So is there a way to do the same thing if x and y are both sparse tensors?

from pytorch_sparse.

KukumavMozolo avatar KukumavMozolo commented on June 18, 2024

This works great, unfortunately in my case this mask = torch.isin(flat_index_x, flat_index_y)is quite slow since one array is quite large so as it turned out using torch.where is actually faster.
Anyhow thank you very much for your suggestion!

from pytorch_sparse.

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