How can I InvokeNamed T to any about do HOT 7 CLOSED

I suppose do.InvokeNamed() should be able to skip the type check when the type is any ?

from do.

I assumed. I just look at where invokeByName (type check) is used.

Thanks for the approval before 2.0

from do.

This is embarrassing. 🫣

Let me think about it.

from do.

Аlso came across this

Seems to be solved by adding (Must)InvokeAsNamed to support not only any.

It just invokeAnyByName().(T), but with cast check in package

from do.

I suppose do.InvokeNamed() should be able to skip the type check when the type is any ?

I think this is a good solution.

from do.

@d-enk in your PR you said we might add the behavior to AsNamed. Can you tell us more about your though?

I don't see in what case we would declare an alias to any.

from do.

from do.