I have a callback that get's bound in lua and from c++ I'd like to invoke that, but <c

similar example... <div class="highlight highlight-source-c++ notranslate position

I've also tried LuaFunction but no luck having <code

this hack seems to work.. <div class="highlight highlight-source-c++ notranslate p

std::function and self about kaguya HOT 3 OPEN

joeroback commented on August 19, 2024

std::function and self

from kaguya.

Comments (3)

joeroback commented on August 19, 2024

similar example...

#include <kaguya/kaguya.hpp>

#include <cstdio>

typedef void (*OnConnectFn)(void);

void somefunction(const std::function<void()>& fn)
{
    fn();
}

extern "C" int luaopen_fn(lua_State *L)
{
    kaguya::State state(L);
    kaguya::LuaTable module = state.newTable();
    module["onConnect"] = kaguya::function(somefunction);
    return module.push();
}

local fn = require 'fn'
local view = {}

function view:onConnect()
    print('onConnect', self)
end

function view:main()
    print('main', self)
    print('fn', fn)
    fn.onConnect(self.onConnect)
end

view:main()

from kaguya.

joeroback commented on August 19, 2024

I've also tried LuaFunction but no luck having self != nil

from kaguya.

joeroback commented on August 19, 2024

this hack seems to work..

#include <kaguya/kaguya.hpp>

#include <cstdio>

typedef void (*OnConnectFn)(void);

void somefunction(kaguya::LuaFunction fn, kaguya::LuaTable self)
{
    fn(self);
}

extern "C" int luaopen_fn(lua_State *L)
{
    kaguya::State state(L);
    kaguya::LuaTable module = state.newTable();
    module["onConnect"] = kaguya::function(somefunction);
    return module.push();
}

local fn = require 'fn'
local view = {}

function view:onConnect()
    print('onConnect', self)
    if self then
        print('onConnect.data', self.data)
    end
end

function view:main()
    self.data = 'foobar'
    print('main', self)
    print('fn', fn)
    fn.onConnect(view.onConnect, self)
end

view:main()
view:onConnect()