Comments (6)
Done in master
from zod-to-json-schema.
Maps are not handled properly
it is not clear how to represent them
Pick one :)
It doesn't matter that it has a preprocess if it can't be guaranteed to be used all the time.
from zod-to-json-schema.
Pick one :)
Ok, fair.
It doesn't matter that it has a preprocess if it can't be guaranteed to be used all the time.
I'd be fine with an opt-in, since either way we build schema explicitly - maybe we could just have a configuration option?
from zod-to-json-schema.
I ended up using this hack:
const coercedMap = <K extends ZodTypeAny, V extends ZodTypeAny>(
keySchema: K,
valueSchema: V,
) =>
z.preprocess(
(arg, ctx) =>
arg === undefined
? new Map()
: new Map(
Object.entries(arg as {}).map(([key, val]) => [
keySchema.parse(key, {
path: [...ctx.path, key, "<key>"],
}),
val,
]),
),
// For JSON Schemas pretend we are an object rather than a map.
tweaks.jsonSchemaHack
? (z.record(keySchema, valueSchema) as never)
: z.map(keySchema, valueSchema),
);
tweaks.jsonSchemaHack
is a global that is toggled on when we export schemas, but is off for everything else.
What I'm looking for is to get rid of the tweaks.jsonSchemaHack
- if it was possible to just tell zod-to-json-schema
I am using z.map
but I want it to look like a z.record
that would be great.
from zod-to-json-schema.
Sure, wth.
from zod-to-json-schema.
Sweet! Thanks!
from zod-to-json-schema.
Related Issues (20)
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- Maximum call stack size exceeded in zodToJsonSchema HOT 15
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from zod-to-json-schema.