Comments (3)
ljharb
commented on June 12, 2024
How does that interact with decorators?
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Mike96Angelo
commented on June 12, 2024
Since decorators require two arguments @<expression that results in a decorator function> <thing to decorate> we can determine that an @ that receives no arguments that follows a |> can be treated as an injection point instead of a decorator.
if we allow directional piping and use directional injection points (@>, <@) there is no conflict with decorators at all.
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MeguminSama
commented on June 12, 2024
@ has been excluded as a topic reference, noted here:
#232 (comment)
#91 (comment)
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Related Issues (20)
- Proposition: supporting both options by making the Hack syntax a sugar syntax for unary functions HOT 5
- Wrong "F# pipes" link? HOT 3
- What if? Use `->` instead `|>` HOT 3
- Solution - Two operators? HOT 1
- Raku-style pipelining with less verbose lambda syntax HOT 1
- Proposal: create a new function instead HOT 8
- Is there a place where we can just say "please no"? HOT 5
- Simpler Syntax HOT 11
- Grammar rules in proposed spec text seem incomplete HOT 2
- Need to make a convincing argument why this can't be a library function HOT 2
- Combine Hack and F# Pipes HOT 4
- Make topic token optional in hack proposal in some cases HOT 6
- New motivation
- I think it would be prudent to walk away from this proposal entirely HOT 12
- Kotlin-style pipelines HOT 3
- Error Handling HOT 1
- Piping streams? HOT 1
- A simpler, proposed alternative to existing proposals HOT 5
- Implementing pipeline operator as a syntax transformer HOT 5
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