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matt-cornell avatar matt-cornell commented on July 2, 2024

LLVM can take arbitrary sized integers, so really even a u128 wouldn't be sufficient. The use of u64 comes from the C++ API (which decides the C API), since 128 bit integers aren't widely supported and don't exactly have great ABI compatibility.
If you want to construct constant integers with more than 64 bits, you can use const_int_from_string which will parse it for a simple solution, or you can use const_int_arbitrary_precision to pass in a slice of u64s, which is generally a better solution.
If you insist on using u128, then this should do what you need:

fn const_int_u128(ty: IntType, val: u128) -> IntValue {

  let bytes = [(val & 0xffffffffffffffff) as u64, (val >> 64) as u64];
  ty.const_int_arbitrary_precision(&bytes)
}

Generally though, 64 bit integers are more than enough.

from inkwell.

Toni-Graphics avatar Toni-Graphics commented on July 2, 2024

Thanks

from inkwell.

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