Can't pass Tuple to Promise#success about brightfutures HOT 3 CLOSED

I had the same problem and solved it by removing the inner set of parentheses in the success call.

from brightfutures.

My example in was a simplified version of what I'm actually doing. That simplified version works by removing the inner set of parentheses but when I do the same when using generics instead of Int, String I still can't get it to work.

Here is an example using generics that doesn't work.

func someFunc<U,V>(someU: U, someV: V) -> Future<(U,V)> {
  var promise = Promise<(U,V)>()

  promise.success( (someU, someV) )

  return promise.future
}

from brightfutures.

I can imagine that this is something that the compiler has trouble with (although it shouldn't). However, I can't seem to reproduce the issue as it seems to work fine for me. I've pasted the following code in BrightFuturesTests.swift and it behaves as expected:

func testSucceedingFutureWithTuple() {

    func someFunc<U,V>(someU: U, someV: V) -> Future<(U,V)> {
        var promise = Promise<(U,V)>()

        promise.success( (someU, someV) )

        return promise.future
    }

    let f = someFunc("BF", 2014)

    let e = self.expectationWithDescription("")

    f.onSuccess { val in
        e.fulfill()
    }

    self.waitForExpectationsWithTimeout(2, handler: nil)
}

Am I missing something? I am using Xcode 6.0.1 (6A317). If this doesn't work for you, could you try to make the parameter of promise.success an @autoclosure to see if that solves the issue? Thanks!

from brightfutures.