how do i recreate a password requirements regex? about magic-regexp HOT 5 OPEN

Hi, just as an aside, "hard" password requirements are actually counter-productive, as a security measure.

For the purpose of checking the safety of a password, you would be better served by something like https://github.com/dropbox/zxcvbn

Nonetheless, have fun with regular expressions!

from magic-regexp.

You can do something like this:

const PASSWORD_RE = createRegExp(
  exactly('')
    .before(char.times.any().and(letter.lowercase))
    .before(char.times.any().and(letter.uppercase))
    .before(char.times.any().and(digit))
    .before(char.times.any().and(charIn('!@#$%^&*')))
    .and(letter.or(digit.or(charIn('!@#$%^&*'))).times.atLeast(8))
    .at.lineStart()
    .at.lineEnd()
)

charIn can just take all characters in one go as a string, but we do still missing Input helper that create custom range(s) to simplify more, ex: for regexp [b-t3-6]

from magic-regexp.

thanks @didavid61202 for your solution, i'll end up closing the issue
but let me first ask you to briefly explain how you ended up with this solution
why there's the need of exactly('')? and .at.lineStart() .at.lineEnd() what they do?

the documentation as i mentioned before isn't that clear

from magic-regexp.

@didavid61202
your solution create regex ^(?=.*[a-z])(?=.*[A-Z])(?=.*\d)(?=.*[!@#$%\^&*])(?:[a-zA-Z]|(?:\d|[!@#$%\^&*])){8,}$
how to create more clear regex like ^(?=.*[a-z])(?=.*[A-Z])(?=.*\d)(?=.*[!@#$%\^&*]).{8,}$

from magic-regexp.

@didavid61202 your solution create regex ^(?=.*[a-z])(?=.*[A-Z])(?=.*\d)(?=.*[!@#$%\^&*])(?:[a-zA-Z]|(?:\d|[!@#$%\^&*])){8,}$ how to create more clear regex like ^(?=.*[a-z])(?=.*[A-Z])(?=.*\d)(?=.*[!@#$%\^&*]).{8,}$

maybe

const regexp = createRegExp(
    exactly(
      exactly('')
        .before(char.times.any().and(letter.lowercase))
        .before(char.times.any().and(letter.uppercase))
        .before(char.times.any().and(digit))
        .before(char.times.any().and(charIn('!@#$%^&*'))),
      char
        .times.atLeast(8),
    )
      .at.lineStart()
      .at.lineEnd()
)

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