Comments (1)
0n3t04ll
commented on June 6, 2024
這兩天分析了這個漏洞，關於出錯位置在我的電腦上是(接續 sub_801BB21)：
result = (*v7)(a2, a3, a4, a5, a6, a7); // 拿 **a1 也就是 0x808b116 當 function pointer
808b116:
0808B2E3 mov eax, [edi+3Ch] ; 從 strcat 就維持相同的值的 edi + 0x3c == 0x12e6d0
0808B308 call dword ptr [eax] ; *(0x12e6d0)
12e6d0 是被 overflow 過去的區域最後的部分，到這邊成功 control flow hijack
關於 12e6d0 是啥？為啥存放 function pointer 就沒什麼頭緒了，不過應該可以確定不是 seh 也不是 return addres
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