Sane indexing last sample doesnt work? about learnapl HOT 6 CLOSED

You're missing the crucial ⎕IO←0. See the first code cell at the top of every chapter. The Indexing chapter intro emphasises this:

But as before, we begin by setting our index origin, extra important as we’re about to discuss indexing.

     ⎕IO←0
      I←⌷⍨∘⊃⍨⍤0 99 
      m ← 3 3⍴(1 2 3)(3 2 1)(4 5 6)(5 3 1)(5 6 8)(7 1 2)(4 3 9)(3 7 6)(4 5 1)
      
      (0 0)(1 2)(2 2)I m
┌→────────────────────────┐
│ ┌→────┐ ┌→────┐ ┌→────┐ │
│ │1 2 3│ │7 1 2│ │4 5 1│ │
│ └~────┘ └~────┘ └~────┘ │
└∊────────────────────────┘

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      ⎕IO←0
      ]DISPLAY m ← 3 3⍴9?9
┌→──────┐
↓┌→────┐│
│↓0 3 5││
││4 2 1││
││7 6 8││
│└~────┘│
└───────┘
      (0 0⍉m) ← ¯1 ¯1 ¯1
      m
┌→───────┐
↓¯1  3  5│
│ 4 ¯1  1│
│ 7  6 ¯1│
└~───────┘

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⎕IO←0 is used exclusively in the book, reasons for which are explained in the first chapter.

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gotcha @xpqz thx, interesting, still didnt get why that was there, maybe skim a lot but could you explain what actually is doing and why it is needed?

For me not being English my first lang, isnt clear why I need to define that (except that doesnt work if I dont do that)... also why it isn't defined in the langauge itself or if there are other ways to define the base index. Or how it is referenecd used by other symbols that are already defined.

I think would be helpful to know why.

Anyway, thanks for the book, still searching more ways to learn about APL, resources seem scarse.

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I think I have it now, ⎕IO prints 1 just starting the repl, so setting it as 0 as "normal" programming.

So I guess that is a variable already defined on system, interesting way of APL to allow changing base index I guess.

Still dont know why I can't use IO←0 but must use ⎕ Quad to set it or display it.

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