Comments (7)
[deleted comment]
from gotube.
this message is written by ext()
you tried to call ext with they parametters :
ext("onclick="open","</a>")
but ext was unable to find this string in "c" (so it reach the end of the
document)
and the state of "p" at this moment was 0
same for :
ext("0,'","&") reachs the limite (from) p=0
Original comment by [email protected]
on 17 Mar 2011 at 10:16
from gotube.
But how is that possible if this is part of html that contains flv
onclick="openReportingForm('frPFYoU4WML',0,'http://v-ec.slutload-media.com/f/r/P
/F/frPFYoU4WML.480.flv?2a8283553d5cb07b981d3deae74443bff6c750d65a992967e522a1a1d
c3830cc41f37249e010a5d43225fac0bddcc1db7ac6558a23de5f89c57e82b827f57ce4b7cfb9813
ae22e2b5d985465f9d9eedb83268bf3d3ea7be40ac176e47e2f441321fd329ffaa78cc3c85a3d7d2
3694ba2e51779a2e3&40');return false">Complain/Report</a>
As I said returns the good url (from the video page) and I really can't find
what's wrong with this
ext('onclick="open', '</a>');
and
b.ext("0,'", "&");
Original comment by [email protected]
on 18 Mar 2011 at 7:17
from gotube.
not tested but try this :
SlutLoad.play = function (url){
c=GetContents(url);p=0;
return ext("',0,'","&");
}
Original comment by [email protected]
on 18 Mar 2011 at 3:21
from gotube.
Thx man. That worked out for me :D
Original comment by [email protected]
on 18 Mar 2011 at 4:28
from gotube.
This is my script
var SlutLoad = new Object();
SlutLoad.rev = 1;
SlutLoad.SearchDesc =
SlutLoad.Name = 'SlutLoad';
SlutLoad.Search = function (keyword, page){
var result = new Object();
result.bypage = 20;
result.start = (page-1)*result.bypage+1;
c = GetContents('http://www.theamateurzone.info/');
result.total = -1
result.VideoInfo = new Array();
while (p = c.indexOf('<li value="1',p)+1){
video = new Object();
video.attr = 1;
video.page = 'http://www.slutload.com'+ext('href="' '" id');
video.Title = ext('', '<img');
video.ThumbnailURL = ext('img src="');
video.Description = ext('class="descr">', '</a>');
// video.LengthSeconds = ext('"box_left">',':')*60+ext(':','<')*1;
// video.ViewCount = ext('<div class="clear_right"></div>','
').replace(/\s+/g,'')*1;
// video.URL =
'unescape(GetContents("'+video.page+'").match("%26file=(.*?)%26t=")[1])';
video.URL = 'SlutLoad.play("'+video.page+'")';
result.VideoInfo.push(video);
}
result.end = result.start-1+result.VideoInfo.length;
return result;
}
SlutLoad.play = function (id){
PSPTube.log(id);
c=GetContents(id);
var b = ext('onclick="open', '</a>');
PSPTube.log(b);
var c = b.ext("0,'", "&");
PSPTube.log(c);
return c;
}
SiteList.push(SlutLoad);
Results works fine but i got this error in log:
http://www.slutload.com/watch/frPFYoU4WML/18-Teen-Strips-and-Plays-on-Webcam-hig
h-school-teen-205.htmlext("onclick="open","</a>") reachs the limite (from) p=0
ext("0,'","&") reachs the limite (from) p=0
The returning link is valid. But getting flv from that page gives error.
Part of html that contains flv:
onclick="openReportingForm('frPFYoU4WML',0,'http://v-ec.slutload-media.com/f/r/P
/F/frPFYoU4WML.480.flv?2a8283553d5cb07b981d3deae74443bff6c750d65a992967e522a1a1d
c3830cc41f37249e010a5d43225fac0bddcc1db7ac6558a23de5f89c57e82b827f57ce4b7cfb9813
ae22e2b5d985465f9d9eedb83268bf3d3ea7be40ac176e47e2f441321fd329ffaa78cc3c85a3d7d2
3694ba2e51779a2e3&40');return false">Complain/Report</a>
Why am i getting this error?
Greets,
iServer
Original comment by [email protected]
on 23 Feb 2012 at 3:56
from gotube.
why are you getting result list from theamateurzone.info
but you are getting the flv from slutload.com ?
btw theamateurzone.info store they flv in the /media/videos/flv/ folder
so you just have to do "/media/videos/flv/"+video.id+".flv" to retreive the url
Original comment by [email protected]
on 23 Feb 2012 at 5:35
from gotube.
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