Giter VIP home page Giter VIP logo

Comments (3)

zishang520 avatar zishang520 commented on September 22, 2024

Hi this code snippet is a simple broadcast example:

custom := io.Of(
	regexp.MustCompile(`/\w+`),
	nil,
)
custom.On("connection", func(clients ...interface{}) {
	socket := clients[0].(*socket.Socket)
	socket.Broadcast().Emit("Broadcast", "To all connected clients except the sender")
	custom.Emit("Broadcast", "broadcast to namespace \\w+ matches")
	io.Emit("Broadcast", "broadcast to the default namespace /")
})

Of course, you can also refer to the socket.io documentation. The usage of this project is similar to socket.io of nodejs

from socket.io.

CodaBool avatar CodaBool commented on September 22, 2024

nice, I have that code snippet working for broadcasting.

For some reason though after leaving and entering a room, broadcast seems to no longer work. Which was why I thought it was something wrong with broadcast. It seems to be more likely that I am leaving and joining a room wrong.

an example

// this will have a client leave their room and join all other existing rooms
// once joining it will make a broadcast to that room
// obviously a weird thing to do
// but I am just trying to prove in a simple way that a client is sharing a room
io.Sockets().Adapter().Rooms().Range(func(sid, value interface{}) bool {

  // skip over your own room
  if socket.Room(client.Id()) != sid.(socket.Room) {

    // prints all rooms
    io.Sockets().Adapter().Rooms().Range(func(room, value interface{}) bool {
      log.Print("  - ", room)
      return true
    })

    log.Print(fmt.Sprintf("%v ➡️  %v", socket.Id(), sid)))

    // leave current room and join a room it found another client on
    client.Leave(socket.Room(socket.Id()))
    client.Join(sid.(socket.Room))

    // prints all rooms
    io.Sockets().Adapter().Rooms().Range(func(room, value interface{}) bool {
      log.Print("  - ", room)
      return true
    })

    client.Broadcast().To(sid.(socket.Room)).Emit("chat", "hi")
  }
  return true
})

there is only one room on the server
img1

despite both clients being the same room, they both receive the broadcast emit
img2

from socket.io.

CodaBool avatar CodaBool commented on September 22, 2024

oh sorry Looks like I should have followed the socket.io docs behavior more. I commented out the socket.Leave(server.Room(socket.Id())) line and it works as expected. I don't think there is anything wrong with your repo. I will close this issue.

from socket.io.

Related Issues (20)

Recommend Projects

  • React photo React

    A declarative, efficient, and flexible JavaScript library for building user interfaces.

  • Vue.js photo Vue.js

    🖖 Vue.js is a progressive, incrementally-adoptable JavaScript framework for building UI on the web.

  • Typescript photo Typescript

    TypeScript is a superset of JavaScript that compiles to clean JavaScript output.

  • TensorFlow photo TensorFlow

    An Open Source Machine Learning Framework for Everyone

  • Django photo Django

    The Web framework for perfectionists with deadlines.

  • D3 photo D3

    Bring data to life with SVG, Canvas and HTML. 📊📈🎉

Recommend Topics

  • javascript

    JavaScript (JS) is a lightweight interpreted programming language with first-class functions.

  • web

    Some thing interesting about web. New door for the world.

  • server

    A server is a program made to process requests and deliver data to clients.

  • Machine learning

    Machine learning is a way of modeling and interpreting data that allows a piece of software to respond intelligently.

  • Game

    Some thing interesting about game, make everyone happy.

Recommend Org

  • Facebook photo Facebook

    We are working to build community through open source technology. NB: members must have two-factor auth.

  • Microsoft photo Microsoft

    Open source projects and samples from Microsoft.

  • Google photo Google

    Google ❤️ Open Source for everyone.

  • D3 photo D3

    Data-Driven Documents codes.