Why not use the <true> if <predicate> else <false> structure instead?
It is a designed feature of the language, not a hack of the type system.

At first I want to thank all of you for your help, didn't expect this to become that big :).

All those contributions lead to fact that we need some kind of structuring.
When I enter this repo I feel a little bit overwhelmed with this amount of files.

The question that raises is "What's the right way?". Order them by data types, differentiate between function, performance and readability tricks, etc.. Maybe you guys even decide, that we should leave it as it is.

Feel free to add your opinion :)

I've made a pull request - #73.

Thought it would be worth an issue to go along side in case it warranted a discussion.

As stated in the pull request:

I think we could justify having a separate file from reverselist for reversing strings and ints.

Some newbies don't have the conceptual leap from slicing lists to slicing strings.

Other possibility is to merge the two into a reverseiterable.py but I feel this is less explicit than two separate files.

Question as title.

https://github.com/brennerm/PyTricks/blob/master/switch.py -
This is not fallthrough as you can expect from switch-case statement ^^"

traditional way

'''
Printing the pattern
*
**
***
****
'''

for i in range(1,4+1):
    for j in range(i):
       print('*', end='')
    print()

hack

print('\n'.join(['*' * i for i in range(1, 4+1)])

grouping adjacent use zip and iter...
some code like this:

lst  = range(10)
group_n = lambda lst, n: zip(*([iter(lst)] * n))
print group(lst, 3)
#output
#[(0, 1, 2), (3, 4, 5), (6, 7, 8)]

Even though it's just an example, sum() function shouldn't be used. Overwriting built-in functions is bad practice (unexpected behavior if wanting to use Python sum()).

How about changing it to product or difference or concat?

https://github.com/brennerm/PyTricks/blame/master/compoundboolstatement.py#L6
Absolutely would not work.
Replace with if 1 and 6 and not 4 in l: to see that the answer is still true.
Python will check only if not 4 in l, as "1 and 6" is True.

! /usr/bin/env python3

"""To find the number of times characters are repeated in a string """

from collections import Counter

Counter('abracadabra').most_common(3)

[('a', 5), ('r', 2), ('b', 2)]

The argument of most_common is the number of items to be returned

Default will return count for all characters

Counter('abracadabra').most_common(1)

[('a', 5)]

I am asking because I am not seeing any response to PR's or issues for quite some time?

Any ideas guys?

Some method of organization, or "index" in the README might be useful. See https://github.com/vinta/awesome-python for an example.

Perhaps part of the users PR to add a trick would be to add an entry in the README?

Traditional way

if a > 7:
    b = '>7'
elif a == 7:
    b = '7'
else:
    b = '<7'

hack

b = '>7' if a > 7 else '7' if a == 7 else '<7'