1. The fizzBuzz function is defined, which takes an integer n as an argument. This function will print the FizzBuzz sequence from 1 to n.

2. A for loop is used to iterate through numbers from 1 to n. The loop variable i represents the current number being processed.

3. Inside the loop, there are conditional statements (if, else if, and else) to determine what to print for each number i.

4. The first condition checks if i is a multiple of both 3 and 5. If i is divisible by both 3 and 5 (i.e., i % 3 === 0 and i % 5 === 0), it prints "FizzBuzz" because it matches both conditions.

5. The second condition checks if i is only a multiple of 3 (i.e., i % 3 === 0). If it is, it prints "Fizz."

6. The third condition checks if i is only a multiple of 5 (i.e., i % 5 === 0). If it is, it prints "Buzz."

7. If none of the above conditions are met (i.e., i is not divisible by 3, 5, or both), the else block is executed, and it prints the current value of i.

8. The loop continues to the next number, and the process repeats until it reaches n, printing the appropriate output for each number along the way.

This code effectively implements the FizzBuzz logic, which replaces numbers divisible by 3 with "Fizz," numbers divisible by 5 with "Buzz," and numbers divisible by both 3 and 5 with "FizzBuzz," while printing all other numbers as-is.