-
The
fizzBuzz
function is defined, which takes an integern
as an argument. This function will print the FizzBuzz sequence from 1 ton
. -
A
for
loop is used to iterate through numbers from 1 ton
. The loop variablei
represents the current number being processed. -
Inside the loop, there are conditional statements (
if
,else if
, andelse
) to determine what to print for each numberi
. -
The first condition checks if
i
is a multiple of both 3 and 5. Ifi
is divisible by both 3 and 5 (i.e.,i % 3 === 0
andi % 5 === 0
), it prints "FizzBuzz" because it matches both conditions. -
The second condition checks if
i
is only a multiple of 3 (i.e.,i % 3 === 0
). If it is, it prints "Fizz." -
The third condition checks if
i
is only a multiple of 5 (i.e.,i % 5 === 0
). If it is, it prints "Buzz." -
If none of the above conditions are met (i.e.,
i
is not divisible by 3, 5, or both), theelse
block is executed, and it prints the current value ofi
. -
The loop continues to the next number, and the process repeats until it reaches
n
, printing the appropriate output for each number along the way.
This code effectively implements the FizzBuzz logic, which replaces numbers divisible by 3 with "Fizz," numbers divisible by 5 with "Buzz," and numbers divisible by both 3 and 5 with "FizzBuzz," while printing all other numbers as-is.