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http://blog.mengoreo.cn/post/vslam_ch3/
个人拙见,如有错误,欢迎评论指出 🤗。
https://mengoreo.github.io/post/deep_learning_book/
Linear Algebra Basic Types Scalars: A scalar is just a single number, usually in lower-case variable names.
Vectors: An array of numbers, with lower case names written in bold typeface. [ \boldsymbol{x} = [ x_1, x_2, \cdots, x_n ]^\top . ]
Matrices: A 2-D array of numbers, usually given in upper-case variable names with bold typeface, Such as (\boldsymbol{M}).
Tensors: An array with more than two axes, denoted by this typeface: (\boldsymbol{\mathsf{A}}) (in latex: \boldsymbol{\mathsf{A}}).
https://www.juicyiter.com/2018/05/08/Hexo-pure/
如果你还没有入坑的话,请点击这里查看。 一番哔哔 这两天吐血熬夜搞了搞 「pure」 主题,网上一大片 「NexT」 的个性化配置教程,的确很美,但是不是我的风格,所以我只能耗费两天,凭着自己的 「推理」 ,自己搞下个性化。 因为学习前端的时候大约是一年前了,而且按时候学的也只是皮毛,所以现在只能靠着推理了。虽只是 「删」 「改」 「增」,但是并不知道作者制作主题时的逻辑结构,只能通过各个文件内的
https://mengoreo.github.io/post/deep-learning-book-in-org-subtree-export/
Linear Algebra Basic Types Scalars: A scalar is just a single number, usually in lower-case variable names.
https://www.juicyiter.com/2018/05/23/pat1006a/
找出最早进去的和最晚出来的。 1234567891011121314151617181920212223242526272829303132333435363738394041#include <stdio.h>#define maxSize 17struct record{ char id[17]; int starthour; int startmin; int star
http://blog.mengoreo.cn/post/learning_opencv/
Mat - The Basic Image Container Mat is basically a class with two data parts: the matrix header (containing information such as the size of the matrix, the method used for storing, at which address is the matrix stored …) and a pointer to the matrix data containing the pixe values. The matrix header size is constant, but the size of the matrix itself may vary.
OpenCV uses a reference counting system.
https://mengoreo.github.io/post/cnn-in-org-subtree-export/
X’s and O’s Figure 1: Determining whether an image is an X or an O
To better understand how CNN works. Consider an simple example. In this example, CNN has one job. Each time we hand it a picture, it has to decide whether it has an X or an O. It assumes there is always one or another.
An naïve approach is solving it to save an image of an X and an O and compare every new image to the exemplars to see which is the better match.
https://www.juicyiter.com/2018/07/26/CSAPP-Chapter-2/
Information Storage A machine level program views memory as a large array of bytes, referred as virtual memory. Each byte of memory is defined by a unique number, known as its address, and the set of
https://www.juicyiter.com/2018/05/23/pat1004a/
叶节点个数,我这里选择的广度搜索。 1234567891011121314151617181920212223242526272829303132333435363738394041424344454647484950515253545556575859606162#include <stdio.h>#define maxSize 100typedef struct familyTre
https://www.juicyiter.com/voices/
播客 The Philosopher's Stone 配音 寂静,如同地狱般的……
https://www.juicyiter.com/2018/07/26/csapp-2/
Information Storage A machine level program views memory as a large array of bytes, referred as virtual memory. Each byte of memory is defined by a unique number, known as its address, and the set of
http://blog.mengoreo.cn/post/vslam_ch1/
个人拙见,如有错误,欢迎评论指出 🤗。
https://www.juicyiter.com/2018/05/23/pat1002a/
多项式相加 123456789101112131415161718192021222324252627282930313233#include <stdio.h>int main(){ int k1,k2; int i,d,k=0;/k is the number of different exponents/ double a[1001]={0},t
https://www.juicyiter.com/2018/07/25/csapp-1/
Files include **text files ** which consist exclusively of ASCII characters and binary files(all other files). Preprocessing phase: Reading the header file and insert it(them) into the C program te
https://www.juicyiter.com/2018/05/23/pat1005a/
类似格式化输出数字了 1234567891011121314151617181920212223242526272829#include <stdio.h>#include <string.h>#define maxSize 102void format(int n){ int i,count=0; char *numbers[]={"zero","on
https://www.juicyiter.com/2018/05/23/pat1003a/
最短路径问题 路径短为首要选择。当最短路径相同时,选择人数多的路径。 123456789101112131415161718192021222324252627282930313233343536373839404142434445464748495051525354555657585960616263646566676869707172737475767778798081828384858687
https://www.juicyiter.com/2019/02/23/EPI-Python-4-1/
Problem The parity of a binary word is 1 is the number of 1s in the word is odd; otherwise, it is 0. For example the parity of 10111 is 0, and the parity of 1011 is 1. How would you calculate the par
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