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This is a small application to understand how Elgamal encryption works.
I think that the calculation of c2 has a problem (missing a "mod p"), because if you do this:
Say the receiver chooses prime p = 71, and g=33 (one can check that 33 is a generator of {\mathbb Z}_{71}^*), and secret exponent x=62. Then h = g^x \bmod 71 = 10. (I won’t explicitly write the “\bmod 71” anymore.) The receiver would publish the public key (p=71, g=33, h=10).
Say a sender wants to send the message m=15. It chooses random exponent r=31, say, computes the ciphertext (g^r, h^rm) = (62, 18), and sends this to the receiver.
From the reference the result will be 870, but in the site, and if you make the calculation, the result should be 18.
I believe that the right formula is c2 = ((h^r mod p) * m) mod p.
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