Bulk replace about regexp2 HOT 6 CLOSED

No problem, I'll poke around to see how easy this is.

from regexp2.

Turns out, it was pretty easy. It's based on the .NET version of the Replace function, so the replacement function MatchEvaluator takes a full Match instead of just a string as input.

func (re *Regexp) ReplaceFunc(input string, evaluator MatchEvaluator, startAt, count int) (string, error)

from regexp2.

Is there a specific behavior you need?

In general the regexp2 engine uses []rune instead of []byte but those are much less common than just having a string, so I left those overloads out in a few places.

The existing replace function in regexp2 is:

func (re *Regexp) Replace(input, replacement string, startAt, count int) (string, error)

You can see from the example usage in replace_test.go that it most aligns with ReplaceAllString. That was the only replacer I needed so I stopped after implementing it.

If you need the literal version (without match expansion) or the function replacer let me know and I'll look into it.

from regexp2.

Thank you very much for answering my question!
I should've noticed that -1 for count works as normal bulk replace. I'd use current Replace function as that.

FYI: this is a quick update I created just now for my interest, removing startAt and count. Ignore this.
https://github.com/hachi8833/regexp2/tree/replaceallstring

from regexp2.

Hello again,

After that, I found that I need 'function replacer' version of Replace function, like ReplaceAllStringFunc.
I'd be very glad if you'd kindly implement that. How about this?

from regexp2.

Thank you very much for your kindness with explanations! I'll look into it.

from regexp2.