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dlclark avatar dlclark commented on August 26, 2024 2

To accomplish this you'll want to use FindNextMatch since it'll re-use the converted []rune for you instead of re-generating a new []rune each time.

func regexp2FindAllString(re *regexp2.Regexp, s string) []string {
	var matches []string
	m, _ := re.FindStringMatch(s)
	for m != nil {
		matches = append(matches, m.String())
		m, _ = re.FindNextMatch(m)
	}
	return matches
}

I'm going to close this issue since this looks like a pretty simple function to implement. However, I will update the README.md to give an example usage of FindNextMatch.

from regexp2.

slimsag avatar slimsag commented on August 26, 2024 1

OK, it turns out I was wrong and both Index and Length are in runes. They are consistent. So my only feedback is points 2 & 3 above 😃

Here is the final working regexp2FindAllString implementation for anyone else who may be looking for one:

func regexp2FindAllString(re *regexp2.Regexp, s string) []string {
	var (
		matches []string
		r = []rune(s)
	)
	for {
		match, _ := re.FindStringMatch(string(r))
		if match == nil {
			break
		} else {
			matches = append(matches, match.String())
			r = r[match.Index+match.Length:]
		}
	}
	return matches
}

(I would send this as a PR, but I realize it is incomplete without the n parameter and proper tests)

from regexp2.

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