how can i use like std:string? there are no operators about tiny-utf8 HOT 7 CLOSED

// Create random genes for mutation
utf8_string mutatedGenes()
{
    int len = genesList.size();
    int r = randomNum(0, len-1);
    //cout << "random char:" << genesList[r] << endl;
    return genesList[r];
}

/home/patrikx3/Projects/sygnus/thermo-range-workspace/thermo-range-server/src/native/test/test-utf8.cpp: In function ‘utf8_string mutatedGenes()’:
/home/patrikx3/Projects/sygnus/thermo-range-workspace/thermo-range-server/src/native/test/test-utf8.cpp:23:23: error: could not convert ‘genesList.utf8_string::operator[](((utf8_string::size_type)r))’ from ‘utf8_string::utf8_codepoint_reference<false>’ to ‘utf8_string’
     return genesList[r];

from tiny-utf8.

Hi!

There is an operator+ for utf8_strings, so you should be able to concatenate them.
And in principle, std::string has no constructor from char, that's why utf8_string doesn't have it either.
What you can do is use the explicit constructor utf8_string( 1 , genesList[r] ).

Does that work for you?

Best regards,
Jakob

from tiny-utf8.

checking out, thanks you very much!

from tiny-utf8.

You're very welcome! Thanks for pointing me to this issue though, I just realized, that I had indeed added a non-explicit constructor with just char32_t, which I now made explicit. You can omit the '1'-parameter if you'd like, but please keep in mind, that this is tiny-utf8 specific :D

from tiny-utf8.

How did it go?

from tiny-utf8.

awesome! thanks!

from tiny-utf8.

Good to hear that, I'm glad!

from tiny-utf8.