I think there is an issue in your solution for 1_wanna_b3_a_r0ck5tar

In the Poetic Number Literals for Rockstar, a hyphen - is counted as another letter.
Therefore a six-string should be 1 10(mod10) = 10 rather than 136

Testing with

A guitar is a six-string        
Say A guitar

on Rockstar Online demonstrates this.

Similarly - a billboard-burning razzmatazz should be 170 rather than 1970

Thanks for posting your workings - really helped me understand Rockstar better!

In the script of finding the 16-bit key, it should not 'break', cause there may be other keys which also can shift to correct PNG pre-16bytes. I've tried 21 keys, and finally found the answer.

https://github.com/Dvd848/CTFs/blob/master/2019_Mossad/Challenge3_files/EncryptSoftware.c

inspect > sources > wasm

I'm playing around with Ghidra and I'm wondering where the strings are?

Your writeup mentions there's a string "Congrats! Your flag is:" but I've grepped and searched and I can't find where that is in the decompiled code.

Thanks for clues!

Hey there, I was working on the flag shop question and I found your writeup for that question. I tried 3333333 for the amount which worked successfully. But when I tried the number 2386093 and 2386094, which gave a negative total cost as expected but the account balance was still negative. I wasn't sure it is because of the program itself, or because of some hidden rule for the extreme cases.
I got 2386093 by dividing 2^31 by 900 since 2^31 is the negative max for 32-bit int.
However, 2386095 works perfectly.

Thanks a lot.

Hi there,

This question may be a bit silly, but it does bother me.
I was doing the problem called ' 1_wanna_b3_a_r0ck5tar '. I have confusion regarding '-'(hyphen) under the poetic number literals part. Based on your solution, correct me if I misunderstood. '-' is kind like separation sign so that 'six-string' is '3' and '6' which although adds up to 10, with '-' we can get 3 and 6 instead of 0. This makes sense to me when it applies to the Music=1970.

However, when I converted the txt to the py using the same package, I got results below.

In which, 'a six-string' = 10, 'a billboard-burning razzmatazz' = 170. Based on the first half definition, six-string sounds right, but the later one doesn't make sense to me. And I do not fully understand the meaning of '13 letters > 3'.

I had tried different combinations, results are attached below.

Thank you in advance.