• Build robust and dynamic Python objects.
• Accomplish complex programming tasks using knowledge from previous modules.

• Class: a bundle of data and functionality. Can be copied and modified to accomplish a wide variety of programming tasks.
• Object: the more common name for an instance. The two can usually be used interchangeably.
• Object-Oriented Programming: programming that is oriented around data (made mobile and changeable in objects) rather than functionality. Python is an object-oriented programming language.
• Function: a series of steps that create, transform, and move data.
• Method: a function that is defined inside of a class.

This is a test-driven lab. Run pipenv install to create your virtual environment and pipenv shell to enter the virtual environment. Then run pytest -x to run your tests. Use these instructions and pytest's error messages to complete your work in the lib/ folder.

You will write a program that, given a word and a list of possible anagrams, selects the correct one(s).

Your class, Anagram should take a word on initialization; instances should respond to a match() instance method that takes a list of possible anagrams. It should return all matches in a list. If no matches exist, it should return an empty list.

In other words, given: 'listen' and ['enlists', 'google', 'inlets', 'banana'] the program should return ['inlets'].

listen = Anagram("listen")
listen.match(['enlists', 'google', 'inlets', 'banana'])
# => ['inlets']

Write your solution in lib/anagram.py.

Once all of your tests are passing, commit and push your work using git to submit.

This is a difficult lab that will require some algorithmic thinking! Try writing some pseudocode and break the problem down into smaller steps before writing out your implementation.

Hints:

How will you determine if one word is an anagram for another?

You'll need to iterate over the list of words that the match() method takes as an argument. You will compare each word of that list to the word that the Anagram class is initialized with.

To determine one word is an anagram of another word, try determining if they are composed of the same letters. You can use a list interpretation on a string to get a list of its individual letters:

[letter for letter in "hello"]
# ["h", "e", "l", "l", "o"]

You can compare two lists using the ==. For example:

[1, 2, 3] == [1, 2, 3]
# => True

[1, 3, 2] == [1, 2, 3]
# => False

Two lists are equal if they contain the same elements, in the same order. Remember that you can use sorted() on a list. This will help in your comparison:

sorted([1, 3, 2]) == sorted([3, 2, 1])
# => True

• 5. Data Structures - Python
• Python sorted() Function - W3schools