p = Permutation([4, 5, 3, 1, 2])
print(p)
print(~p)  # Invert
print(p.order)
print(p.cycleform)
print(p.cycle_structure)
print(p.isDerangement())
print(p.isEven())
print(p ** 51, p ** -64)  # Quick power, due to using order
print(p.matrix())

# Example of (2, 3, 7) cycle in S15 group.
print(Permutation.generateExampleOfCertainStruct([2, 3, 7], 15))
# Find count of (2, 2, 2)-cycles in S8 group
print(PermutationUtils.countOfCertainCycleform([2, 2, 2], cardinality=8))

# Find count of permutation, whuch commuting with (3, 3)-cycles in S10
print(PermutationUtils.countOfCommutingWithCycleform([3, 3], cardinality=10))

# Graph part
drawRootGraph(6)

drawCommutativeGraph(5)

drawStabilizingGraph(5)