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if (likely(!rt_overloaded(this_rq))) 注释

/*如果当前队列的 root_domain 的 rto_count 不为 0,说明已经过载了,无需拉任务进来*/
if (likely(!rt_overloaded(this_rq)))
    return;

这里的意思应该是如果 this_rq 所在的 rd 下没有过载的 cpu,就没有 pull 的必要了,直接返回

内核抢占的矛盾点疑问

arch/x86/entry/entry_64.S这个文件中retint_kernel里jnc 1f这段是判断cf标志位,在它的上一句bt $9 EFLAGS(%rsp)中,应该获取的是eflags的第九位if标志到cf中,如果中断是开启的,此时cf应该是1,为什么在这里反而是判断cf是0呢?

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