SQLCover.CodeCoverage.Stop() gives Exception calling "Stop" with "0" argument(s): "Value cannot be null. Parameter name: source" about sqlcover HOT 7 CLOSED

@GoEddie, do you have any advice on this issue?

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Are you settting the name of the database in the connection string to the temporary database?

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@GoEddie, thank you for your suggestion. I did not, but I did just try this now and with this change I get the same error:
$temporaryConnectionStringWithInitialCatalog = "$temporaryConnectionString;Initial Catalog=$database"
$coverage = New-Object SQLCover.CodeCoverage($temporaryConnectionStringWithInitialCatalog, $database)

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I can't help thinking that the error is something to do with the connection string, that error isn't generated by SQLCover but (I think) by the sql connection. Try using this for the connection string "server=servername;integrated security=sspi;" instead of data source.

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"server=servername;integrated security=sspi;" with MS SQL instance name changed gives the same error. I'm not able to identify where in the SQLCover source code such error can arise. Still I have confirmed that the error definitely occur on this line: "$coverageResults = $coverage.Stop()" and that "$coverage.Start()" returns without an error.

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If you download the source, you can debug it by passing true for the debug flag to Start - then if you attach visual studio it should stop on the line where the exception occurs.

I’d turn on logging as well.

To get to those flags you call the constructor without the defaults.

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This issue has now been resolved although I don't understand the cause of the exception. All versions I built myself from source code in the Git repository using the latest Visual Studio Community 2019 does not produce this exception.

https://github.com/GoEddie/SQLCover/archive/0.5.0.zip: Exception
922d7d2: No exception (Debug & Release)
https://github.com/GoEddie/SQLCover/tree/0.5.0-p: No exception (Release)
https://github.com/GoEddie/SQLCover/tree/0.5.0: No exception (Release)

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